2x^2+18/7x-428=0

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Solution for 2x^2+18/7x-428=0 equation: 


x in (-oo:+oo)

2*x^2+(18/7)*x-428 = 0

2*x^2+18/7*x-428 = 0

DELTA = (18/7)^2-(-428*2*4)

DELTA = 168100/49

DELTA > 0

x = ((168100/49)^(1/2)-18/7)/(2*2) or x = (-(168100/49)^(1/2)-18/7)/(2*2)

x = 14 or x = -107/7

x in { -107/7, 14 }

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